cos(2x)+(10*sin^2(x))=7

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Solution for cos(2x)+(10*sin^2(x))=7 equation: 


Simplifying
cos(2x) + (10sin2(x)) = 7

Remove parenthesis around (2x)
cos * 2x + (10sin2(x)) = 7

Reorder the terms for easier multiplication:
2cos * x + (10sin2(x)) = 7

Multiply cos * x
2cosx + (10sin2(x)) = 7

Multiply in2s * x
2cosx + (10in2sx) = 7

Solving
2cosx + (10in2sx) = 7

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '(-10in2sx)' to each side of the equation.
2cosx + (10in2sx) + (-10in2sx) = 7 + (-10in2sx)

Combine like terms: (10in2sx) + (-10in2sx) = 0
2cosx + 0 = 7 + (-10in2sx)
2cosx = 7 + (-10in2sx)

Divide each side by '2osx'.
c = 3.5o-1s-1x-1 + (-5in2o-1)

Simplifying
c = 3.5o-1s-1x-1 + (-5in2o-1)

Reorder the terms:
c = (-5in2o-1) + 3.5o-1s-1x-1

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